If anyone can get the answer to this, they get a cookie and much respect from me. I'm telling you now you'll get it wrong.
What is:
1+2+3+4+5+6+7+.......+infinity-1+infinity (obviously including all numbers inbetween)?
Get ready to do some wrong guessing.
I used to be relevant.
A LARGE NUMBER
So, do you give cookies in cheque form?
I like it.
Logically speaking you can't add infinity to anything as then what was stated as infinity is not infinity as infinity is greater than any finite (real or natural) number, however large.
Undefined.
Theoretically it should be infinity, but since infinity has no numerical value it cannot be added those numbers.
Er, I'm going to have to go with infinity on this one.
looking good and dressing well is a necessity. having a purpose in life is not.
At 1/9/07 03:46 PM, Cosmonautical wrote: Anything plus infinity = infinity.
Not in this case.
At 1/9/07 03:46 PM, parzo wrote: Is it infinity?
No.
At 1/9/07 03:47 PM, scottmale24 wrote: n, where n = answer
Nice try.
At 1/9/07 03:47 PM, Simkiss wrote: A LARGE NUMBER
So, do you give cookies in cheque form?
Perhaps, if it wasn't for the fact that your answer was completely wrong. And i mean completely wrong.
At 1/9/07 03:48 PM, Jelly-On-The-Telly wrote: Theoretically it should be infinity, but since infinity has no numerical value it cannot be added those numbers.
i has no numerical value, but can still be added to numbers.
Keep guessing guys. Here's a clue: it's negative.
At 1/9/07 03:52 PM, Cybex wrote: Here's a clue: it's negative.
-1
1+2+3+4+5+6+7+.......+infinity-1+infinity???
jesus... ill just say infinity.... cause you dont know what 'infinity' stands for....
Well adding all those numbers would equal infinity. However subtracting 1 from infinity cancels out infinity, thus it can only be infinity symbol-1
Here I am, bored with everything.
My first guess would be one less than infinity, but I somehow don't think that's right now :-\
You can't add or subtract an idea. That's like saying:
1+83-FREEDOM=???
At 1/9/07 03:45 PM, Cybex wrote:
1+2+3+4+5+6+7+.......+infinity-1+infinity (obviously including all numbers inbetween)?
Get ready to do some wrong guessing.
Let's say I interpret it this way.
1+2+3+4+5+6+7+....infinity. This means it's just infinity. seeing as you have dots.
Now lets say you multiplied it by -1, meaning it is negative infinity. And then + infinity, meaning the answer is 0.
Please tell me it has nothing to do with nullity, that would be lame.
At 1/9/07 03:56 PM, Idiosyncratic wrote: Well adding all those numbers would equal infinity. However subtracting 1 from infinity cancels out infinity, thus it can only be infinity symbol-1
Wrong. Incase people didn't get what i meant, i meant What number do you get if you add every integer from 1 to infinity. Sorry if i confused people with the "infinity-1", that was just meant to show that the series has a constant pattern right up to the end.
Root minus one?
Come on Cyborg; just tell us the goddamn answer!
At 1/9/07 03:45 PM, Cybex wrote: If anyone can get the answer to this, they get a cookie and much respect from me. I'm telling you now you'll get it wrong.
What is:
1+2+3+4+5+6+7+.......+infinity-1+infinity (obviously including all numbers inbetween)?
Get ready to do some wrong guessing.
i believe that
if infinity = x
it would be 2x-1
(n+1) x (n / 2) = sum of numbers 1 to n
n = infinity
There wouldn't be an answer since it just goes on and on...
GT: Born2Evil
At 1/9/07 03:58 PM, Cybex wrote: Wrong. Incase people didn't get what i meant, i meant What number do you get if you add every integer from 1 to infinity. Sorry if i confused people with the "infinity-1", that was just meant to show that the series has a constant pattern right up to the end.
nevermind, in that case with x = infinity
itd be 2x
This is a question that cannot be answered correctly because the actual question is incorrect.
A
At 1/9/07 03:45 PM, Cybex wrote: If anyone can get the answer to this, they get a cookie and much respect from me. I'm telling you now you'll get it wrong.
What is:
1+2+3+4+5+6+7+.......+infinity-1+infinity (obviously including all numbers inbetween)?
Get ready to do some wrong guessing.
infinity now where is my cookie
Do I earn the right of a PM because of my mega-bot-skills? :D
At 1/9/07 03:58 PM, Paranoia wrote: Root minus one?
No, it's a real number
Come on Cyborg; just tell us the goddamn answer!
You haven't suffered enough yet.
At 1/9/07 03:56 PM, CrimsonEdge wrote: You can't add or subtract an idea. That's like saying:
i is just an idea but you can add and subtract that.
At 1/9/07 03:58 PM, Akula wrote: Please tell me it has nothing to do with nullity, that would be lame.
Nothing to do with nullity
At 1/9/07 03:58 PM, xXShadowStalkerXx wrote: i believe that
if infinity = x
it would be 2x-1
Believe away. You're wrong though.
At 1/9/07 03:59 PM, brainface wrote: (n+1) x (n / 2) = sum of numbers 1 to n
n = infinity
Not a valid answer.
At 1/9/07 04:01 PM, xXShadowStalkerXx wrote: nevermind, in that case with x = infinity
itd be 2x
If you say so. Now what's that as a real number?
At 1/9/07 04:03 PM, Worthless-Wisdom wrote: This is a question that cannot be answered correctly because the actual question is incorrect.
*Automated "you're wrong" message*
You guys are going to hate me when i tell you the answer.
This is cybex
I wrote the question slightly wqrong. I meant this:
1+2+3+4+5.....+(infinity-2)+(infinity-1)+(inf inity)=?
It's meant to be like that. So in words, what is the sum of all integers from 1 to infinity? There is a real number which is the answer to this question.
42, because it answers everything and is completley original.
Oh sod it; I'm at least going to try to work this out.
Does it have anything to do with Pascal's triangle?
Sum of terms to n = (n + 1)C3
nCr = n! / (r!(n - r)!)
if n = infinity
(n + 1)C3 = infinity! / 6(infinity - 3)!
That's as far as I've got.
